Matematika Sekolah Dasar Q.
[tex] \\ [/tex]
[tex] \sqrt{625} + (10 \times 2) + 5 = [/tex]
[tex] \\ [/tex]
nt: sangat kecanduan :)
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Q.
[tex] \\ [/tex]
[tex] \sqrt{625} + (10 \times 2) + 5 = [/tex]
[tex] \\ [/tex]
nt: sangat kecanduan :)
________________________​

« Penyelesaian Soal »

[tex] \: [/tex]

[ Soal ]

[tex] \sqrt{625} + (10 \times 2) + 5 = ?[/tex]

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  • √625 + ( 10 × 2 ) + 5
  • = ( √25² ) + ( 20 ) + 5
  • = ( 25 + 20 + 5 )
  • = (( 25 + 25 ))
  • = 50

Kesimpulan

  • Maka, Hasil = 50

Detail jawaban

  • Kelas : 4/SD
  • Mapel: Matematika
  • Materi: Akar dan pangkat 2
  • Kode soal : 2
  • Kode kategorisasi : -

Semoga Bisa Bermanfaat-!

Penjelasan dengan langkah-langkah:

[tex]\sqrt{625} + (10 \times 2) + 5 \\ \\ =25 + (10 \times 2) + 5 \\ \\ = 25 + 20 + 5 \\ \\ = 45 + 5 \\ \\ \boxed{ =50 }[/tex]

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