Q.
[tex] \\ [/tex]
[tex] \sqrt{625} + (10 \times 2) + 5 = [/tex]
[tex] \\ [/tex]
nt: sangat kecanduan :)
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[tex] \\ [/tex]
[tex] \sqrt{625} + (10 \times 2) + 5 = [/tex]
[tex] \\ [/tex]
nt: sangat kecanduan :)
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« Penyelesaian Soal »
[tex] \: [/tex]
[ Soal ]
[tex] \sqrt{625} + (10 \times 2) + 5 = ?[/tex]
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- √625 + ( 10 × 2 ) + 5
- = ( √25² ) + ( 20 ) + 5
- = ( 25 + 20 + 5 )
- = (( 25 + 25 ))
- = 50
Kesimpulan ←
- Maka, Hasil = 50
Detail jawaban ←
- Kelas : 4/SD
- Mapel: Matematika
- Materi: Akar dan pangkat 2
- Kode soal : 2
- Kode kategorisasi : -
Semoga Bisa Bermanfaat-!
Penjelasan dengan langkah-langkah:
[tex]\sqrt{625} + (10 \times 2) + 5 \\ \\ =25 + (10 \times 2) + 5 \\ \\ = 25 + 20 + 5 \\ \\ = 45 + 5 \\ \\ \boxed{ =50 }[/tex]
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